T=2h^2+70h+50

Solution for T=2h^2+70h+50 equation:

=2T^2+70T+50

We move all terms to the left:

-(2T^2+70T+50)=0

We get rid of parentheses

-2T^2-70T-50=0

a = -2; b = -70; c = -50;
Δ = b2-4ac
Δ = -702-4·(-2)·(-50)
Δ = 4500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4500}=\sqrt{900*5}=\sqrt{900}*\sqrt{5}=30\sqrt{5}$
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-30\sqrt{5}}{2*-2}=\frac{70-30\sqrt{5}}{-4}
$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+30\sqrt{5}}{2*-2}=\frac{70+30\sqrt{5}}{-4}
$